Question

Calculate the amount of water (g)

produced by the combustion of 16 g

of methane.​

Answer 1

Answer:

Hope helpful to you.

Explanation:

According to the above equation, one mole of CH4 (16 g) on combustion gives one mole of carbon dioxide and 2 moles of water and 2 moles of water = 2 x [2 + 16] = 36 g of water.

Answer 2

The balanced equation for the combustion of methane is :

$\small\bold{CH_4 (g) + 2O_2 (g) → CO_2 (g) + 2H_2O (g)}$

(i)16 g of CH4 corresponds to one mole.

(ii) From the above equation, 1 mol of

$CH_4$ (g) gives 2 mol of $H_2O$(g).

2 mol of water $(H_2O)$ = 2 × (2+16)

= 2 × 18 = 36 g

$\bold{1 \: mol \: H_2O = 18 g \: H_2O }$

$\bold{\implies \frac{18gH_2O}{1 \: mol \: H_2O}}$

Hence,

$\bold{2 \: mol \: H_2O \: \times \frac{18g \: H_2O}{1 \: mol \: H_2O}}$

$\bold{= 2 × 18 g \: H_2O = 36 g \: H_2O}$