Question

calculate the amount of water produced by the combustion of 32 gram of Methane

Answer 1

72 grams of water will be produced.

Explanation: Combustion reaction is a type of reaction in which hydrocarbon is decomposed in the presence of air to form carbon dioxide and water.

Reaction for combustion of methane is written as:

As combustion is done in the presence of air, hence oxygen gas is present in excess and is therefore, considered as excess reagent.

Methane is considered as the limiting reagent because it limits the formation of product.

Moles can be calculated by:

   ....(1)

Molar mass of methane = 16 g/mol

By stoichiometry,

1 mole of methane produces 2 moles of water

Hence, 2 moles of methane will produce =

Water produced = 4 moles,

Amount of water can be calculated by using equation 1, we get

Molar mass of water = 18 g/mol

Amount of water produced = 72 grams.

Answer 2

Answer:

72g of water

Explanation:

    CH4(g) + 2O2(g) GIVES CO2 (g) + 2H2O(g)

As per the stoichinometric equation

combine of 1mole (16g) CH4   produce  2 moles (2  multiplied 18 =36)of water

                                             

                                    CH4

                             (12)  +     (4 MULTIPLE 1)  =  16 g  mol-1

                                    H2O

           (  2 MULTIPLE 1)+(1 MULTIPLE 16)   = 18 g mol-1

           combusion of 32 g CH4 produces

           32gH2OmDIVIDED 16 CH4 MULTIPLIED 32gCH4

                                    = 72 g of water

                      hence the answer...............

           HOPE YOU LOVE MY ANSWER............