Question

Calculate the amount of water produced on combustion of 360 gm of glucose (C6H12O6).​

Answer 1

Answer:

GIVEN,

360 gm of glucose,

mass of glucose is 180

moles of C6H12O6 = 360/180 = 2 moles.      

CHEMICAL REACTION :

C6H12O6 + 6O2 --------> 6CO2 + 6H2O

FROM,

Above reaction 6 mole of H2O Produced

so, mass of H2O is => 18 x 6

                               => 108 gm