Calculate the amount of water required to prepare 250 g of 5% solution of glucose by mass
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given:
Mass of solute= x
Mass of solvent= y
Mass of solution= 250g
concentration Mass by mass= 5% = mass of solute/mass of solution*100
5=x/250 * 100
25*5 = 10x
x= 125/10
x= 12.5g
Mass of solvent=mass of solution - mass of solute
y=250-12.5
y= 237.5g
therefore 237.5 grams of water is required
Mass of solute= x
Mass of solvent= y
Mass of solution= 250g
concentration Mass by mass= 5% = mass of solute/mass of solution*100
5=x/250 * 100
25*5 = 10x
x= 125/10
x= 12.5g
Mass of solvent=mass of solution - mass of solute
y=250-12.5
y= 237.5g
therefore 237.5 grams of water is required
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