calculate the amount of water required to prepare 500 gram of 2.5 % of solution of sugar
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Mass percent = mass of solute / mass of solution .
Where mass of solution = mass of solute + mass of solvent
Here mass of solution = 500g
Mass percent = 2.5 %
Let the mass of solute be x.
Then 2.5 % = x / 500
⇒ x = 12.5g
Hence mass of sugar is 12.5 g
∴ mass of solvent = mass of solution - mass of solute
∴ mass of solvent = 500 g - 12.5g
⇒ mass of solvent = 487.5 g
Hence 487.5 g of water is required to prepare 500g of 2.5 % sugar solution.
Where mass of solution = mass of solute + mass of solvent
Here mass of solution = 500g
Mass percent = 2.5 %
Let the mass of solute be x.
Then 2.5 % = x / 500
⇒ x = 12.5g
Hence mass of sugar is 12.5 g
∴ mass of solvent = mass of solution - mass of solute
∴ mass of solvent = 500 g - 12.5g
⇒ mass of solvent = 487.5 g
Hence 487.5 g of water is required to prepare 500g of 2.5 % sugar solution.
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