Question

calculate the amount of water required to prepare 600g of 3%of solution of sugar​

Answer 1

Explanation:

Mass percent = mass of solute / mass of solution .

Where mass of solution = mass of solute +  mass of solvent

Here mass of solution = 600g

Mass percent = 3 % 

Let the mass of solute be x.

Then 3 %  = x / 600

⇒ x = 18g

Hence mass of sugar is 18g

∴ mass of solvent = mass of solution - mass of solute

∴ mass of solvent = 600 g - 18g

⇒ mass of solvent = 582g 

Hence 582 g of water is required to prepare 600g of 3 % sugar solution.