Question

Calculate the amount of work done 5moles of an ideal gas expands isothermally and reversibly at 27°c from 10Atm to 2 Atm​

Answer 1

Explanation:

Work done by the system(w)

= −nRTlog

e

P

2

P

1

=2.303nRTlog

P

2

P

1

=−2.303×5×8.314×300log

2

10

=−20.075×10

3

J

Let M be the mass which can be lifted through a height of 1 m.

Work done in lifting the mass

=Mgh=M×9.8×1 J

So, M×9.8=20.075×10

3

M=2048.469 kg