Question

Calculate the amount of work done if a cell of 120 v passes current of 5A if in a ckt. for 10 second ?​

Answer 1

Answer:

given,

p.d= 120V

I=5A

T= 20 sec

then,

(work is equal to heat produce , so instead of W we can write H)

H=VIT

now ,H= 120*5*10

=6000 joules (the unit of work and heat is same)

Answer 2

Required Answer:

Given:

• Voltage ( V ) = 120v

• Current ( I ) = 5 A

• Time taken ( t ) = 10 seconds

To calculate:

• Amount of work done ( W )

Formula Used:

• $\sf { V = \dfrac{W}{Q} }$

• $\sf { I = \dfrac{Q}{t} }$

Where,

V = voltage

W = Work done

Q = charge

I = current

t = time

Calculation:

Here, we can find the work done by voltage/potential difference formula:

• $\sf { V = \dfrac{W}{Q} }$

Let us calculate the charge (Q) first:

We know that,

• $\sf { I = \dfrac{Q}{t} }$

$\sf { \longrightarrow 5 = \dfrac{Q}{10} }$

$\sf { \longrightarrow Q = 5 \times 10 }$

$\sf { \longrightarrow Q = 50 \: C }$

Therefore, charge flowing through it is 50 C.

Substituting all the values:

• $\sf { V = \dfrac{W}{Q} }$

$\sf { \longrightarrow 120 = \dfrac{W}{50} }$

$\sf { \longrightarrow W = 120 \times 50 }$

$\sf { \longrightarrow W = 6000 \: J}$

Therefore, amount of work done is 6000 J or 6 kJ.

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