Question

Calculate the amount of work done in carrying a charge of 5mc against a potential difference of 100v.

Answer 1

Given:

A charge of magnitude 5 mC is moved from one point to another against a potential difference of 100 V

To find:

The amount of work done in moving the charge.

Concept:

Potential difference between 2 points is defined as the the amount of work done required to transport a unit positive charge in between the two specified points.

In other words , we can say that potential difference is calculated by the ratio of the total work done to the the magnitude of charge transported.

Calculation:

$\therefore \: \sf{potential \: difference = \dfrac{work}{charge} }$

$= > \: \sf{100 = \dfrac{work}{5 \times {10}^{ - 3} } }$

$= > \: \sf{ work = 5 \times {10}^{ - 3} \times 100}$

$= > \: \sf{ work = 5 \times {10}^{ - 1} }$

$= > \: \sf{ work = 0.5 \: joule }$

So final answer:

$\boxed{ \red{ \large{ \bold{\: \sf{ work \: done \: is \: 0.5 \: joule }}}}}$

Answer 2

Given ,

Charge (q) = 5 mc or 5 × (10)^-3 c

Potential difference (v) = 100 v

We know that ,

The work done to move a unit charge from one point to another point is called potential difference

It is denoted by " v "

The SI unit of potential difference is " volt "

Thus ,

$\sf \mapsto 100 = \frac{w}{5 \times {(10)}^{ - 3} } \\ \\\sf \mapsto w = 100 \times 5 \times {(10)}^{ - 3} \\ \\\sf \mapsto w = 5 \times {(10)}^{ - 1} \\ \\ \sf \mapsto w = 0.5 \: \: j$

$\therefore \sf \underline{The \: work \: done \: is \: 0.5 \: j}$