Question

calculate the amount of work done in lifting a heavy load of 50 kg up to the height of 3m g= 10​

Answer 1

Answer:

M= 50kg

g= 10

(distance) S= 3m

W= mgh

W=50×10×3

W= 1500J

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Answer 2

Given,

Mass of a heavy lead = 50 kg

Height = 3 m

g = 10 m/s^2

To Find,

The amount of work done in lifting the heavy lead =?

Solution,

We can solve the question using the following steps:

The work done on a mass m is equal to,

$W = Fd = mgh$

Here, $m =$ Mass of the object

           $h =$ Height

Substituting the given values in the above equation,

$W = 50*10*3$

     $=1500 J$

Hence, the amount of work done in lifting a heavy load is 1500 J.