Calculate the amount of work done in moving a charge of 5 c across a conductor connected across a source providing potential diff of 6 v
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Answered by
2
Q = 5C
V =6V
W=?
V=W/C
6= W/5
W = 5×6
= 30J
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0
Charge=5 Q
Potential difference=6V
Since, V=W/Q
W=VQ
W=6×5=30
Hence, work done is 30Joule.
.....hope it will help✌.....
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