Question

calculate the amount of work done in rotating a dipole of dipole moment 3x10^-8cm , from its position of stable equilibrium to the position of unstable equilibrium in a uniform electric field of intensity 10^4N/C.​

Answer 1

Answer:

frm roteating the dipole of the stable equilibrium by any angle thita  the amount of  work done

w = pe(1- cosФ)

fr unstable Ф =180°

w= pe (1 -(-1))          ║ cos 180 =-1

2*pe =w

2*3*10^-8 *10^4 =0.0006 j