Physics, asked by ak8640940, 2 months ago

Calculate the amount of work done in rotating a dipole, of dipole moment 2 x 10 cm, from its

position of stable equilibrium to the position of unstable equilibrium, in uniform electric field of

intensity 5 x 10* N/C​

Answers

Answered by lata40386
4

Answer:

Given: p = 3.2 x 10- 8Cm, E = 104 N/C.

To Find: Work done in rotating dipole (W)

Formula: W = pE (cos θ0 - cos θ)

Calculation:

= 6.4 × 10-4 J.

Work done in rotating an electric dipole is 6.4 × 10-4 J.

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