Calculate the amount of work done in shifting a charge of 2 Columbus from a point A to B having potentials 10V and 5V respectively
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Answered by
29
Work = q ΔV
= 2 C × (10 V - 5 V)
= 10 Joule
∴ 10 J of work is done.
= 2 C × (10 V - 5 V)
= 10 Joule
∴ 10 J of work is done.
Answered by
16
Change in voltage = Work done / charge.
ΔV = W/q .
=> W = qΔv.
=> W = 2 ( 10 - 5 )
=> W = 10J.
Amount of work done is 10J
ΔV = W/q .
=> W = qΔv.
=> W = 2 ( 10 - 5 )
=> W = 10J.
Amount of work done is 10J
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