Question

Calculate the amount of work done in shifting a charge of 2 coulomb from a point A to B having potentials 110V and 25 V respectively.

Answer 1

hey mate!

work done = qV din theta

here,
w (i) = 2*110=220j

w (f) = 2*25 =50j

amount of work done

wf - wi = (220 - 50 ) j

= 170 joule.

#Phoenix