Physics, asked by abhishabhandari, 1 year ago

Calculate the amount of work done in shifting a charge of 2 coulomb from a point A to B having potentials 110V and 25 V respectively.

Answers

Answered by Anonymous
2
hey mate!

work done = qV din theta

here,
w (i) = 2*110=220j

w (f) = 2*25 =50j

amount of work done

wf - wi = (220 - 50 ) j

= 170 joule.

#Phoenix
Anonymous: what's the ans?
abhishabhandari: Actually the ans is not given in the book ...i just wanted to know the process...thanks
Anonymous: :-)
Anonymous: don't worry... its correct
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