Question

Calculate the amount of work done in shifting of charge of 2 C from a point A to B
having potentials +10v and -5v respectively.

Answer 1

Answer:

30 joules

Explanation:

it is given that potential of two points are , 10v and -5v

so potential difference is

10v - (-5v) = 15v

so,

as p.i.= work done / charge moved

= work done= pi * charge

work done = 15 * 2 = 30joules

Answer 2

Given ,

Charge (q) = 2 C

The potential at A and B are 10 v and - 5 v

We know that ,

The work done to move a unit charge from one point to another point is called potential difference

$\large \mathtt{ \fbox{ v_{b} - v_{a} = \frac{w_{ab} }{q} }}$

Thus ,

- 5 - 10 = w/2

-15 = w/2

w = -30 joule

Hence , the work done to move a unit charge from A to B is -30 joule