calculate the amount of work done to carry 4 MC of charge from a point at hundred volt to a point at 120 volt
Answers
Answer:
work done = q(v2 - v1)
= 0.004×(120 -100)
=0.004×20
=0.08
Answer:
IF The charge in Mega Coulomb (MC) 80 Mega Joule (MJ) OR If the charge is in Mili coulomb (mc) 0.08 J
Step-by-step explanation:
Q = 4MC= 4 × 10^6C. ( as 1MC- 10^6C)
V1= 100V
V2 = 120V
So, V = V2- V1
V = 120-100
V = 20V.
We know , Work done = Q × V
= 4 × 10^6 × 20
= 80 × 10^6 Joule.
= 80MJ
OR
IF THE CHARGE IS IN Mili coulomb (mc)Then Q = 0.004C.
V1= 100V
V2 = 120V
So, V = V2- V1
V = 120-100
V = 20V.
We know , Work done = Q × V
= 0.004 × 20
= 0.08Joule.