Question

Calculate the amount of work done to dissociate a system of three charges 1 μC, 1 μC and -4 μC placed on the vertices of an equilateral triangle of side 10 cm?
I want the solution ​

Answer 1

Answer:

की तरफ देख सकता था टाइगर टाइगर को दुत्कारा से खेल में सतीश धवन कॉमेडी शो मैड में अपने अंदाज नहीं पता नही होता वो अपनी ओर खींचने

Answer 2

Answer:

• Here q1=q2=1×10^-6C
• and q3=-4×10^-6C
• also distance X=10cm=1/10m
• since the charges are dissociated so amount of work done is taken as negative
• Then amount of work done is given by
• W= -1/4πepsilon naught ×10(q1q2+q2q3+q3q1)
• = -9×10^9 ×10 [{1×10^-12 }+{-4×10^-12 }+ {-4×10^-12}]
• ={ - 9×10^10 }× {-7×10^-12}
• =63×10^-2
• =63/100
• =0.63J