Question

Calculate the amount of work done when a charge of 500 microcoulomb is moved between the two points at the potential of 120 volt and 100 volt

Answer 1

Q=500×10^-6 C=5×10^-4C

∆V=120-100

∆V=20

work done

=Q∆V

=5×10^-4C×20

=100×10^-4C

=10^-2

I hope this helps ( ╹▽╹ )