Question

Calculate the amount of work performed when 80 L of helium gas expands irreversibly to a final volume of 150 L against 1 bar of pressure.

Answer 1

11th/Chemistry

Thermodynamics

Answer :

Initial volume of He gas = 80L

Final volume of He gas = 169L

Pressure on gas = 1bar

We have to find work done by gas$.$

➤ For expansion/compression of a gas, work done is given by

• W = - P × ∆V

P denotes pressure

∆V denotes change in volume

★ Conversion :

• 1.01325 bar = 1 atm

Therefore, 1 bar = 1/1.01325 = 0.987 atm

★ Calculation :

⭆ W = - P × ∆V

⭆ W = - 0.987 × (150-80)

⭆ W = - 0.987 × 70

⭆ W = - 69.09 atm L

Cheers!