Question

Calculate the amount of work performed when 80 L of helium gas expands irreversibly to a final volume of 150 L against 1 bar of pressure.​

Answer 1

$\Huge {\orange {\bf {\underline {\underline {AnSwer}}}:-}}$

→ Initial volume of He gas = 80L

→ Final volume of He gas = 169L

→ Pressure on gas = 1bar

We have to find work done by gas..

For expansion/compression of a gas, work done is given by

W = - P × ∆V

here,

P = pressure

∆V = change in volume

1.01325 bar = 1 atm

Therefore, 1 bar = 1/1.01325 = 0.987 atm

→ W = - P × ∆V

→ W = - 0.987 × (150-80)

→ W = - 0.987 × 70

→ W = - 69.09 atm L