Question

calculate the amount of work required to stop a truck of mass 5 tons which is moving at 36km per hours​

Answer 1

Answer:

the fricition is

$\frac{1}{200?}$

mass of truck - 5tan

speed = 36 km / HR = 10 m/s

using the coefficient fruition omg = ma

using formula of fraction

f/w = 4mg / mg

f/w = u

f/w = u

put value of equation of motion

f/w = V2 -42 /25

put the value of formula

f/w - 100/2*10*1000

f/w - 1/200

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Answer 2

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