Calculate the amount of work required to stop a truck of mass 5 tones which is moving at 36 km/hr.
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Step-by-step explanation:
the fricition is
\frac{1}{200?}
200?
1
mass of truck - 5tan
speed = 36 km / HR = 10 m/s
using the coefficient fruition omg = ma
using formula of fraction
f/w = 4mg / mg
f/w = u
f/w = u
put value of equation of motion
f/w = V2 -42 /25
put the value of formula
f/w - 100/2*10*1000
f/w - 1/200
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Calculate the amount of work required to stop a truck of mass 5 tones which is moving at 36 km/hr.
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