Calculate the amount of work to be done to convert 100g of ice at 0°C to water at 100°C . (Latent heat of ice =80 cal/g, mechanical equivalent of heat, J=4.2J/cal)
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Total heat supplied,
H=100×80+100×1×(100−0)
=8000+10000=18000cal
∴ Work done, W=JH=4.2×18000=75600J.
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