Chemistry, asked by tanishtarar, 10 months ago

calculate the amount present in grams 1.75 mole of caco3

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Answered by Anonymous

0

Answer:

ѕσlutíσn❤. Molecular mass of CaCO3. = 40 + 12 + 3*16. = 100u. It means 1 mole = 100g. Hence 10 g = 0.1 mole.

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