Question

Calculate the amount the heat required to melt 50 g of ice (0°C) in Kcal/Kg Given the latent heat of fusion
of ice is 80cal/g
Write an answer​

Answer 1

Answer:

Hope it helps u

Explanation:

Q = ml

Q = Heat Given

m = 50g

Latent heat of fusion of ice = 80cal/g

∴Q=50×80

= 4000 cal

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