Calculate the amplitude of the shm represented by x =5root2 (sin2pit+cos2pi)m
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This is a very unusual function.
This is a sinusoidal curve which has its horizontal axis at x = 3.535 = 5/√2
The maxima are all at 11.44 and the minima are all at x = – 4.37
This means that the Amplitude must be 11.44 – 3.535 = 7.905 =5√5/√2
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