Question

calculate the angle between a 2N force and a 3N force so that their resultant is 4N​

Answer 1

$\red\bigstar$ Explanation $\red\bigstar$

We know that,

$\rm R² = A² + B² + 2AB\cos\theta$

Given,

R = 4 N

A = 2 N

B = 3 N

Therefore,

16 = 4 + 9 + 12$\cos\theta$

16 = 13 + 12$\cos\theta$

3 = 12$\cos\theta$

$\cos\theta$ = $\frac{1}{4}$

$\theta$ = $\cos^{-1}(\frac{1}{4})$