Question

Calculate the angle between a 2n force and a 3n force so that their resultant is 4n

Answer 1

Let the angle is a.

so magnitude of resultant..

4^2 =3^2 + 2^2 +2(2)(3)cosa

=>16 = 9+4+12cosa
=>3=12cosa
=>cosa=1/4
=>a=cos^-1(1/4)

so the angle is cos^-1(1/4)