Calculate the angle of deviation for angle of
Incidence 45° when the ray passes through
om equilateral prism such that angle of
incidence is equal to angle of emergence.
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Answer:
Given: A ray of light passes through an equilateral prism such that angle of incidence is equal of emergence and the later is equal to (
4
3
)
th
of the angle of prism.
To find the angle of deviation.
Solution:
If angle of incidence be i, angle of emergence be e and angle of prism be A.
According to the given criteria,
i=e=
4
3
A.......(i)
Angle of deviation for the light in prism is,
δ=i+e−A
⟹δ=2i−A (as given i=e)
⟹δ=2(
4
3
A)−A (from eqn(i))
⟹δ=
2
3−2
A=
2
1
A
As the prism is an equilateral triangle, all the angles of the prism is equal to
60
∘
each, i.e., A=60
∘
δ=
2
1
×60=30
∘
is the angle of deviation.
Explanation:
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