calculate the angles marked with small letters in the following diagram
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in this question b=39,a=51
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a + b = 90 (angle of rectangle)
ANGLE POS = 78 (LP)
POS = QOR = 78 (VOA)
Similarly, POQ = ROS = 102
Since diagonals bisect each other,
QO = OR = OS = OP
Since QO = OR,
Angles OQR = ORQ = a
In Triangle OQR,
a + a = 102 (Ext angle property)
So a = 51
Since a + b = 90
51 + b = 90
b = 39
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