Question

calculate the angles of the parallelogram ABCD from the following figures and plz give me step by step explanation

Answer 1

a)

Here the angles are :

x+3/2x = 180° [Property of a parallelogram]
2x+3x/2 = 180°

5x = 180°×2

5x = 360°

x = 360/5 = 72°


The second angle = 180°-72° = 108° .

b) In this figure

Angle A = Angle D = 70°

Angle D + Angle B = 180°

70°+Angle B = 180°

Angle B = 180°-70° = 110° .

C)

2x+3x = 180°

5x = 180°

x = 180/5 = 36°

2x = 2(36) = 72°

3x = 3(36) = 108° .

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Answer 2

 ❤Here is your solutions ❤

[a]in this figure we will find x :-

x+3/2x = 180° (using Property of a parallelogram)

2x+3x/2 = 180°

5x = 180°×2

5x = 360°

x = 360/5

X= 72° ✔

The second angle = 180°-72° = 108° .✔

[b] In this figure we will find x :-

Angle A = Angle D = 70°

Angle D + Angle B = 180°

70°+Angle B = 180°

Angle B = 180°-70°

Angle B = 110° .✔

[C] in this we will find x :-

2x+3x = 180°

5x = 180°

x = 180/5 = 36° ✔

Angle A = 2x = 2(36) = 72° ✔

Angle B = 3x = 3(36) = 108° .✔

Hope it helps you