Question

calculate the angular speed of a body vibrating at 50 cycles per second

Answer 1

Answer:

1 cycle = 3600 = 2π rad

∴ 50 cycle = 2 π rad × 50 = 100 πrad

∴ = angular speed = 50 cycles per seconds = 100 π rads−1

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Answer 2

The angular speed of the vibrating body is 314.16 radians per second.

As per the given information,

Frequency = 50 cycles per second

Following equation: gives the angular speed of a vibrating body.

ω = 2πf

where

f is the frequency in cycles per second and is the angular speed in radians per second (also known as Hertz).

Hence, the angular speed for a body vibrating at 50 cycles per second would be:

ω = 2π × 50

= 314.16 radians per second (rounded to two decimal places)

Hence, the angular speed of the vibrating body is nearly 314.16 radians per second.

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