Question

calculate the angular speed of rotation of earthso that the Apparent G on the equator is equal to zero ​

Answer 1

Explanation:

Apparent

\begin{lgathered}g = go - w {}^{2} r \\\end{lgathered}

g=go−w

2

r

w = \sqrt{ \frac{g}{r} }w=

r

g

= \sqrt{ \frac{9.8}{6.4 \times {10}^{6} } }=

6.4×10

6

9.8

= 1.27 \times {10}^{ - 3}=1.27×10

−3