calculate the angular speed of the tip of minute hand 10cm long
Answers
Answer:
Given –Radius of tip of minute hand = r = 0 cm
= 0.1 mAs minute hand takes one hour to complete one rotation (i.e. 360o or 2 π radian)
The time period of the tip of minute hand can be given as= T=1hr = 60 min = 3600 sec
The angular velocity of any particle performing circular motion can be given as time rate of change of angular displacementW =
(dt)
(dθ)
W=
TW
(2π)
=
3600W
(2×3.14)
=1.745×10−3rad/sec
The linear velocity (v) at the tip of minute hand is
V=r×ω
V=0.1×1.745×10−3V=1.7451×0−4m/s
Explanation:
Given –Radius of tip of minute hand = r = 0 cm
= 0.1 mAs minute hand takes one hour to complete one rotation (i.e. 360o or 2 π radian)
The time period of the tip of minute hand can be given as= T=1hr = 60 min = 3600 sec
The angular velocity of any particle performing circular motion can be given as time rate of change of angular displacementW =
(dt)
(dθ)
W=
TW
(2π)
=
3600W
(2×3.14)
=1.745×10−3rad/sec
The linear velocity (v) at the tip of minute hand is
V=r×ω
V=0.1×1.745×10−3V=1.7451×0−4m/s
Answer:
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