calculate the angular velocity and linear velocity of a tip of minute hand of length 10cm
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Calculate the angular velocity and linear velocity of a tip of minute hand of length 10 cm.
SolutionGiven –Radius of tip of minute hand = r = 0 cm = 0.1 mAs minute hand takes one hour to complete one rotation (i.e. 360o or 2 π radian)The time period of the tip of minute hand can be given as= T = 1hr = 60 min = 3600 secThe angular velocity of any particle performing circular motion can be given as time rate of change of angular displacementW = (dθ)/ (dt)W= (2 π) / TW= (2 X 3.14 ) / 3600W= 1.745 X 10 -3 rad / secThe linear velocity (v) at the tip of minute hand isV = r X wV = 0.1 X 1.745 X 10 -3V = 1.745 X 10 -4 m/s
SolutionGiven –Radius of tip of minute hand = r = 0 cm = 0.1 mAs minute hand takes one hour to complete one rotation (i.e. 360o or 2 π radian)The time period of the tip of minute hand can be given as= T = 1hr = 60 min = 3600 secThe angular velocity of any particle performing circular motion can be given as time rate of change of angular displacementW = (dθ)/ (dt)W= (2 π) / TW= (2 X 3.14 ) / 3600W= 1.745 X 10 -3 rad / secThe linear velocity (v) at the tip of minute hand isV = r X wV = 0.1 X 1.745 X 10 -3V = 1.745 X 10 -4 m/s
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