Calculate the angular velocity and linear velocity of a tip of minute hand of length 10 cm.
(Ans : 1.745 x 10⁻³ rad/s, 1.745 x 10⁻⁴ m/s)
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Given –
Radius of tip of minute hand = r = 0 cm = 0.1 m
As minute hand takes one hour to complete one rotation (i.e. 360o or 2 π radian)
The time period of the tip of minute hand can be given as
= T = 1hr = 60 min = 3600 sec
The angular velocity of any particle performing circular motion can be given as time rate of change of angular displacement
W = (dθ)/ (dt)
W= (2 π) / T
W= (2 X 3.14 ) / 3600
W= 1.745 X 10 -3 rad / sec
The linear velocity (v) at the tip of minute hand is
V = r X w
V = 0.1 X 1.745 X 10 -3
V = 1.745 X 10 -4 m/
Radius of tip of minute hand = r = 0 cm = 0.1 m
As minute hand takes one hour to complete one rotation (i.e. 360o or 2 π radian)
The time period of the tip of minute hand can be given as
= T = 1hr = 60 min = 3600 sec
The angular velocity of any particle performing circular motion can be given as time rate of change of angular displacement
W = (dθ)/ (dt)
W= (2 π) / T
W= (2 X 3.14 ) / 3600
W= 1.745 X 10 -3 rad / sec
The linear velocity (v) at the tip of minute hand is
V = r X w
V = 0.1 X 1.745 X 10 -3
V = 1.745 X 10 -4 m/
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