Question

calculate the angular velocity and linear velocity of tip of minute hand of length 10 cm. 1.745× 10–⁴

Answer 1

 Calculate the angular velocity and linear velocity of a tip of minute hand of length 10 cm.

SolutionGiven –Radius of tip of minute hand = r  = 0 cm    = 0.1 mAs minute hand takes one hour to complete one rotation (i.e. 360o or 2 π radian)The time period of the tip of minute hand can be given as=  T            =      1hr           =  60 min      = 3600 secThe angular velocity of any particle performing circular motion can be given as time rate of change of angular displacementW = (dθ)/ (dt)W= (2 π) / TW= (2 X 3.14 ) / 3600W= 1.745 X 10 -3 rad / secThe linear velocity (v) at the tip of minute hand isV = r X wV = 0.1  X 1.745 X 10 -3V = 1.745 X 10 -4 m/s

Answer 2

Solution :- l = r = 10cm =10 ×10 –² min = 10–¹ min

T=60min =66×60=3600 sec =3.6×10³sec

Tofind:-(1)w(2)d

We know that

W= 2 Pi open t

=2×3.142 opon 3.6×10³ 7