Question

Calculate the angular velocity of a particle moving along the straight line given by θ = 3t3 + 6t + 2 when t = 5s.​

Answer 1

Answer:

231

Explanation:

here,

Angular velocity

= d(O)/ dt

= d(3t³ + 6t +2)/dt

= 9t² + 6

So, angular velocity at t=5 sec

= 9*(5)² +6

= 225 +6

= 231