calculate the angular velocity of an hour hand of length 1 cm of a clock.
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Answer:
1.745 X 10 -4 m/s
Explanation:
Given –Radius of tip of minute hand = r = 0 cm = 0.1 mAs minute hand takes one hour to complete one rotation (i.e. 360o or 2 π radian)The time period of the tip of minute hand can be given as= T = 1hr = 60 min = 3600 secThe angular velocity of any particle performing circular motion can be given as time rate of change of angular displacementW = (dθ)/ (dt)W= (2 π) / TW= (2 X 3.14 ) / 3600W= 1.745 X 10 -3 rad / secThe linear velocity (v) at the tip of minute hand isV = r X wV = 0.1 X 1.745 X 10 -3V = 1.745 X 10 -4 m/s
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angular velocity = 2π/24 hrs = π/12 rad/hr
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