Question

Calculate the apparent wavelength of a radiation of wavelength 6560 A° emitted by a galaxy which is recedes us with a speed 3000 km/s. (a)Lower by 6 A。 (b)Lower by 65 A° (c)Higher by 6 A° (d)Higher by 66 A°

Answer 1

Answer:

The apparent wavelength due to motion of the galaxy is Higher by 66 A°

Explanation:

As we know by Doppler's equation of apparent frequency is given as

$\frac{\Delta \nu}{\nu} = \frac{v}{c}$

so we know that

$\frac{\frac{1}{\lambda} - \frac{1}{\lambda'}}{\frac{1}{\lambda}} = \frac{v}{c}$

$\frac{\lambda' - \lambda}{\lambda'} = \frac{3\times 10^6}{3\times 10^8}$

$1 - \frac{\lambda}{\lambda'} = 0.01$

so we have

$\Delta \lambda = 0.01 \lambda'$

$\Delta \lambda = 0.01 (6560 A^o)$

$\Delta \lambda = 66 A^o$

So wavelength is increased by 66 A°

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Topic : Dopplers Effect of light

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