Question

calculate the approximate rise of a liquid of density 10^3 kgm^-3 in a capillary tube of length 0.05m and radius 0.2 * 10^-3m. given surface tension of the liquid for the material of that capillary is 7.27*10^-2Nm^-1.​

Answer 1

Answer:

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Explanation:

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Answer 2

Given info : a liquid of density 10³ kg/m³ in a capillary tube of length 0.05 m and radius 0.2 × 10¯³ m. surface tension of the liquid for the material of the capillary is 7.27 × 10¯² N/m

To find : The rise of the liquid in the capillary tube is...

solution : The formula for capillary rise is given by, h = 2S/ρrg

where S is surface tension,

ρ is density of the liquid,

r is the radius of tube and

g is acceleration due to gravity.

here, S = 7.27 × 10¯² N/m, ρ = 10³ kg/m³ , r = 0.05 m and g = 10 m/s²

so, h = (2 × 7.27 × 10¯²)/(10³ × 0.05 × 10)

= 14.54 × 10¯²/500

= 2.908 × 10¯⁴ m

= 0.2908 mm ≈ 0.3 mm

Therefore the rise of a liquid in the capillary tube is 0.3 mm(approx)