Calculate the area of a quadrilateral ABCD when length of the diagonal AC = 10 cm and
the lengths of perpendiculars from B and Don AC be 5 cm and 6 cm respectively.
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Answer:
1) Area of triangle-1/2bh
= 1/2 x 10x5=25cm2
2) Area of triangle = 1/2 x 10x6=30cm2
Total area-25 +30 = 55cm2
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