calculate the area of a quadrilateral ABCD when length of the diagonal AC equal to 15 cm and the length of perpendicular from B and D on ACB 8 cm and 10 cm respectively
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Step-by-step explanation:
I am assuming that the diagonal of 10 divides the quadrilateral into two triangles
One triangle apex is a and the other apex is b
Then, assuming that the prependicular from a to the diagonal is 5
And the perpendicular from b to the same diagonal is 6.
The task then is to calculate the area of both triangles separately then sum the two areas.
1/2 x 10 x 5 = Area 1
1/2 x 10 x 6 =Area 2
Area 1 + Area 2 = 55 sq units
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