Question

calculate the area of
a quadrilateral
ABCD when length of the diagonal AC=10cm and the lengths of perpendicular from B and D on AC be 5 cm and 6 cm respectively​

Answer 1

Step-by-step explanation:

Area of quadrilateral ABCD is 55 \mathrm{cm}^{2}cm

2

Given:

Length of diagonal = 10 cm,

Length of perpendicular from B = 5 cm,

From D = 6 cm

To find:

Area of a quadrilateral

Solution:

Area of a quadrilateral ABCD = Area of triangle ABC + Area of triangle ADC

Area of a quadrilateral ABCD =\left(\frac{1}{2} \times A C \times 5\right)+\left(\frac{1}{2} \times A C \times 6\right)=(

2

1

×AC×5)+(

2

1

×AC×6)

\begin{gathered}\begin{array}{l}{=\left(\frac{1}{2} \times 10 \times 5\right)+\left(\frac{1}{2} \times 10 \times 6\right)}\\ \\ {=\left(\frac{50}{2}\right)+\left(\frac{60}{2}\right)} \\ \\{=25+30}\end{array}\end{gathered}

=(

2

1

×10×5)+(

2

1

×10×6)

=(

2

50

)+(

2

60

)

=25+30

Area of quadrilateral ABCD = 55 \mathrm{cm}^{2}cm

2

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