Question

Calculate the area of a trapezium in cm²,lengths of whose parallel sides (represented by a and b ) and distance between them (h) are: a=5m,b=50cm,h=50dm. (explain)​

Answer 1

Answer:

area of trapezium = 1/2 * distance between two parallel sides * ( sum of two parallel sides)

therefore here

area = 1/2 * 15 * (24+20)

= 1/2 * 15 * 44

= 22 *15

330 sqcm

Answer 2

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

Given:

• Length of parallel sides = 5m(500cm) & 50cm
• Height = 50dm = 500cm

To Find:

• Area of trapezium

Solution:

$\setlength{\unitlength}{1.5cm}\begin{picture}\thicklines\qbezier(0,0)(0,0)(1,2.2)\qbezier(0,0)(0,0)(4,0)\qbezier(3,2.2)(4,0)(4,0)\qbezier(1.5,2.2)(0,2.2)(3,2.2)\put(0.8,2.4){ \bf A }\put(3,2.4){ \bf D }\put(-0.3,-0.3){ \bf B }\put(4,-0.3){ \bf C }\put(4.4,0){\vector(0,0){2.2}}\put( 4.4, 0){\vector(0,-1){0.1}}\put(4.6,1){ \bf 500\ cm }\put(0, -0.5){\vector(1,0){4}}\put(0, -0.5){\vector( - 1, 0){0.1}}\put(1.7, - 0.9){ \bf 500\ cm }\put(0.8, 2.8){\vector(1,0){2.5}}\put(0.8, 2.8){\vector( - 1, 0){0.1}}\put(1.7, 3){ \bf 50\ cm }\end{picture}$

$\text{We know that,}\\\longrightarrow</p><p>Area\: of \:a \:trapezium = \dfrac{1}{2} * (sum\:of\:parallel\:sides) * height. \\So,\\\\\implies Area\: of \:the\:trapezium = \dfrac{1}{2\!\!\!/_{\:\:_1}} * (500+50) * 500\!\!\!\!/^{^\:\:\:\:\:250} \\\\\implies Area\: of \:the\:trapezium = 550 * 250 \\\\\bf{\implies Area\: of \:the\:trapezium = 137500cm^2}$

Hope it helps!