Question

calculate the area of a triangle with sides 6m, 8m and 10m in length.

Answer 1

Answer:

please refer the image

Step-by-step explanation:

Answer 2

$\large\underline\mathrm\purple{Given:}$

$\red{\longrightarrow}$side 1 = 6cm

$\red{\longrightarrow}$side 2 = 8cm

$\red{\longrightarrow}$side 3 = 10cm

$\large\underline\mathrm\purple{To~Find:}$

$\red{\longrightarrow}$Area of the triangle

$\large\underline\mathrm\purple{Formula:}$

$\red{\longrightarrow}$$\mathrm\red{Heron's Formula}$

$\sqrt {(s)(s - a)(s - b)(s - c)} = \: area \: of \: a \: trianle$

$\red{\longrightarrow}$s = semiperimeter

$\red{\longrightarrow}$a = side 1

$\red{\longrightarrow}$b = side 2

$\red{\longrightarrow}$c = side 3

$\large\underline\mathrm\purple{Calculation:}$

$\mathrm{Semiperimeter =}$

$\frac{(6 + 8 + 10)}{2} = \frac{24}{2} = 12cm$

$Area = \sqrt{12(12 - 6)(12 - 8)(12 - 10)} \\ \\ \sqrt{12 \times 6 \times 4 \times 2 \: } \\ \\ \sqrt{2 \times 2 \times 3 \times 2 \times 3 \times 2 \times 2 \times 2} \\ \\ 2 \times 2 \times 2 \times 3 \\ \\ 24$

$\large\underline\mathrm\purple{Solution:}$

$\large\boxed{\rm{\red{24cm²}}}$