Question

Calculate the area of an isosceles triangle with sides of 8 cm, 8 cm and 6 cm

Answer 1

Answer:

24cm square

Step-by-step explanation:

First you multiply 8x6 which is 48 then divide by 2, which is 24.

hope this helps.

Answer 2

Answer:

A = 22.26 sq units

Step-by-step explanation:

It is an isosceles triangle so the two sides have equal values.(8 & 8)

hence 6 is base of the triangle

bh/2 is area formula of a triangle

it refers 2 triangles are take place in a square or rectangle or in parallellogram

ex: breath x height is the area formula for square and rectangle

(breath x height)/2 is triangle formula

In this sum we dont know the value height....

so we need to find height (h)

In this, we need to use Pythagorean theorem:

(side 1)2 + (side 2)2 = (hypotenuse)2

or simply,

a2+b2=c2

before that we want to slice this tringle into two offs vertically on vertex of base's mid point (6/2=3)

we consider

(a) base (b)/2-----> side 1 ===> b/2= 6/2= 3

(b) height (h) -----> side 2 ===> h=?

(c) hypotenuse(x)------> side 3 ===> x=8

now we use Pythagorean theorem:

         a2+b2=c2                            ^2 ==> *sq

  (b/2)^2 + h^2 = x^2

  (6/2)^2 + h^2 =8^2

  3^2 + h^2 =8^2

   9 + h^2 = 64

     h^2 =64-9 =55

    h = $\sqrt{55}$

    h = 7.42 cm

now we can find the Area

            A = 1/2(b x h)

           A = 1/2(6 x 7.42)

             A =  44.52/2

               A = 22.26 sq units