Question

calculate the area of cross section of a wire of langth 2m. its, resistance is 25ohm and the resistivity of material of wire is 1.84×10.6ohm-m.
PLEASE GIVE ME CORRECT ANSWERS. ..​

Answer 1

Answer:

Given:

length=2m

resistence=25ohm

resistivity=1.84×10.6ohm-m.

We know that ,

Resistance = (resistivity*length)/area

25 = (1.84*10^-6*2)/area

area = (3.68*10^-6)/25

area = (0.736*10^-6)/5

area = 0.1472*10^-6

area = 1.472*10^-7 m^2

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Answer 2

Answer:

1.47 × 10⁻³ cm²

Explanation:

Given :

Length L = 2 m

Resistance R = 25 Ω

Resistivity ρ = 1.84 × 10⁻⁶  Ω m

We're asked to find cross section area A :

We know :

R =  ρ L / A

= > A =  ρ L / R

Putting value here we get :

= > A = ( 1.84 × 10⁻⁶ ) . ( 2 ) / 25 m²

= > A =   ( 1.84 × 10⁻⁶ ) . ( 0.08 ) m²

= >  A =   ( 1.84 × 10⁻⁶ ) . ( 0.08 ) . 10⁴ cm²

= > A = 0.1471 × 10⁻² cm²

= > A = 1.47 × 10⁻³ cm²

Hence we get required answer!