Question

calculate the area of cross section of a wire of length 2 metre its resistance is 250 and the resistivity of material of wire is 1.84 into 10 raise to power minus 6 ohm metre​

Answer 1

$\red{\mid{\underline{\overline{\textbf{Answer}}}\mid}}$

Area of cross section :

$1.472 \times {10}^{ - 7} {m}^{2}$

$\red{\mid{\underline{\overline{\textbf{explanation}}}\mid}}$

Resistance of a conductor is the opposition force on charges applied by a conductor to current flowing thought it. Resistance of a conductor is the ratio of product of its resistivity and length to area.It is represented by the expression :

Resistance = Resistance × Length of conductor / Area of cross section.

$\bigstar \: \blue{\mid{\underline{\overline{\textbf{coming \: to \: question}}}\mid}}$

In this case we have been given a conductor with its resistance, resistivity and its lenth, the area of cross section of conductor is not known, we have to calculate it.

In this case we have :

• Resistance = 250 Ohm
• Resistivity = 1.84 × 10^ -6 Ohm m
• Length of conductor = 2m
• Area of Cross section = A = ?

Now after inputting the known values in the discussed expression we get :

$\bigstar \: 250 = \frac{1.84 \times {10}^{ - 6} \times 2 }{a}$

$a = \frac{1.84 \times {10}^{ - 6} \times 2 }{250}$

$a = \frac{1.84 \times {10}^{ - 6} }{125}$

$a = 1.47 \times {10}^{ - 7} {m}^{2}$

Therefore the area of cross section of given conductor is 1.47 × 10^-7 m^2.

______________________________________

BY SCIVIBHANSHU

THANK YOU

STAY CURIOUS